🛠️ JEE➗ Maths

The value of the integral : \(\int \frac{\sin \theta \sin 2\theta \left({\sin }^{6}\theta +{\sin }^{4}\theta +{\sin }^{2…

Q1

The value of the integral : \(\int \frac{\sin \theta \sin 2\theta \left({\sin }^{6}\theta +{\sin }^{4}\theta +{\sin }^{2}\theta \right)\sqrt{2{\sin }^{4}\theta +3{\sin }^{2}\theta +6}}{1-\cos 2\theta }d\theta\) (where c is a constant of integration)

[JEE Main 2021, 25 Feb (Shift 1)]

a

\(\frac{1}{18}{\left[9-2{\sin }^{6}\theta -3{\sin }^{4}\theta -6{\sin }^{2}\theta \right]}^{\frac{3}{2}}+c\)

b

\(\frac{1}{18}{\left[11-18{\cos }^{2}\theta +9{\cos }^{4}\theta -2{\cos }^{6}\theta \right]}^{\frac{3}{2}}+c\)

c

\(\frac{1}{18}{\left[11-18{\sin }^{2}\theta +9{\sin }^{4}\theta -2{\sin }^{6}\theta \right]}^{\frac{3}{2}}+c\)

d

\(\frac{1}{18}{\left[9-2{\cos }^{6}\theta -3{\cos }^{4}\theta -6{\cos }^{2}\theta \right]}^{\frac{3}{2}}+c\)

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