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An angle of intersection of the curves, \(\frac{{x}^{2}}{{a}^{2}}+\frac{{y}^{2}}{{b}^{2}}=1\) and \({x}^{2}+{y}^{2}=ab,a…

Q1

An angle of intersection of the curves, \(\frac{{x}^{2}}{{a}^{2}}+\frac{{y}^{2}}{{b}^{2}}=1\) and \({x}^{2}+{y}^{2}=ab,a>b\) is:

[JEE Main 2021, 31 Aug (Shift 2)]

a

\({\tan }^{-1}\left(\frac{a+b}{\sqrt{ab}}\right)\)

b

\({\tan }^{-1}\left(\frac{a-b}{\sqrt{ab}}\right)\)

c

\({\tan }^{-1}(2\sqrt{ab})\)

d

\({\tan }^{-1}\left(\frac{a-b}{2\sqrt{ab}}\right)\)

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