A wire of length $20 m$ is to be cut into two pieces. A piece of length $l_1$ is bent to make a square of area $A_1$ and the other piece of length $l_2$, is made into a circle of area $A_2$. If $2 A_1+3 A_2$ is minimum then $\left(\pi l_1\right): l_2$ is equal to:

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A wire of length \(20 m\) is to be cut into two pieces. A piece of length \(l_1\) is bent to make a square of area \(A_1…

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