$\lim _{t\to 0}{\left({1}^{\frac{1}{{\sin }^{2}t}}+{2}^{\frac{1}{{\sin }^{2}t}}+\ldots +{n}^{\frac{1}{{\sin }^{2}t}}\right)}^{{\sin }^{2}t}$ is equal to [JEE Main 2023, 24 Jan (Shift 1)]

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\(\lim _{t\to 0}{\left({1}^{\frac{1}{{\sin }^{2}t}}+{2}^{\frac{1}{{\sin }^{2}t}}+\ldots +{n}^{\frac{1}{{\sin }^{2}t}}\ri…

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