Let the matrix $A=\left[\begin{array}{lll}0 & 1 & 0 \ 0 & 0 & 1 \ 1 & 0 & 0\end{array}\right]$ and the matrix $B_0=A^{49}+$ $2 A^{98}$. If $B_n=\operatorname{Adj}\left(B_{n-1}\right)$ for all $n \geq 1$, then $\operatorname{det}\left(B_4\right)$ is equal to

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Let the matrix \(A=\left[\begin{array}{lll}0 & 1 & 0 \\ 0 & 0 & 1 \\ 1 & 0 & 0\end{array}\right]…

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Let the matrix \(A=\left[\begin{array}{lll}0 &amp; 1 &amp; 0 \\ 0 &amp; 0 &amp; 1 \\ 1 &amp; 0 &amp; 0\end{array}\right]…

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Let the matrix \(A=\left[\begin{array}{lll}0 & 1 & 0 \\ 0 & 0 & 1 \\ 1 & 0 & 0\end{array}\right]…