Plotting \(1 / \Lambda_{\mathrm{m}}\) against \(\mathrm{c} \Lambda_{\mathrm{m}}\) for aqueous solutions of a monobasic w…
Q1
Plotting \(1 / \Lambda_{\mathrm{m}}\) against \(\mathrm{c} \Lambda_{\mathrm{m}}\) for aqueous solutions of a monobasic weak acid (HX) resulted in a straight line with \(\mathrm{y}\)-axis intercept of \(\mathrm{P}\) and slope of \(\mathrm{S}\). The ratio \(\mathrm{P} / \mathrm{S}\) is
\(\left[\Lambda_{\mathrm{m}}=\right.\) molar conductivity
\(\Lambda_{\mathrm{m}}^{\circ}=\) limiting molar conductivity
\(\mathrm{c}=\) molar concentration
\(\mathrm{K}_{\mathrm{a}}=\) dissociation constant of HX]
[JEE Advanced 2023, Paper-1]
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