🛠️ JEE🧪 Chemistry

Plotting \(1 / \Lambda_{\mathrm{m}}\) against \(\mathrm{c} \Lambda_{\mathrm{m}}\) for aqueous solutions of a monobasic w…

Q1

Plotting \(1 / \Lambda_{\mathrm{m}}\) against \(\mathrm{c} \Lambda_{\mathrm{m}}\) for aqueous solutions of a monobasic weak acid (HX) resulted in a straight line with \(\mathrm{y}\)-axis intercept of \(\mathrm{P}\) and slope of \(\mathrm{S}\). The ratio \(\mathrm{P} / \mathrm{S}\) is

\(\left[\Lambda_{\mathrm{m}}=\right.\) molar conductivity

\(\Lambda_{\mathrm{m}}^{\circ}=\) limiting molar conductivity

\(\mathrm{c}=\) molar concentration

\(\mathrm{K}_{\mathrm{a}}=\) dissociation constant of HX]

[JEE Advanced 2023, Paper-1]

a

\(\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\circ}\)

b

\(\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\circ} / 2\)

c

\(2 \mathrm{~K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\circ}\)

d

\(1 /\left(\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\circ}\right)\)

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