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Two vectors \(\vec{X}\) and \(\vec{Y}\) have equal magnitude. The magnitude of \((\vec{X}-\vec{Y})\) is \(n\) times the …

Q1

Two vectors \(\vec{X}\) and \(\vec{Y}\) have equal magnitude. The magnitude of \((\vec{X}-\vec{Y})\) is \(n\) times the magnitude of \((\vec{X}+\vec{Y})\). The angle between \(\vec{X}\) and \(\vec{Y}\) is:

[JEE Main 2014, 12 April]

a

\({\cos }^{-1}\left(\frac{{n}^{2}+1}{{n}^{2}-1}\right)\)

b

\({\cos }^{-1}\left(\frac{-{n}^{2}-1}{{n}^{2}-1}\right)\)

c

\({\cos }^{-1}\left(\frac{{n}^{2}-1}{-{n}^{2}-1}\right)\)

d

\({\cos }^{-1}\left(\frac{{n}^{2}+1}{-{n}^{2}-1}\right)\)

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