If $A=\left[\begin{array}{cc}1 & 5 \ \lambda & 10\end{array}\right], A^{-1}=\alpha A+\beta I$ and $\alpha+\beta=-2$, then $4 \alpha^2+$ $\beta^2+\lambda^2$ is equal to: [JEE Main 2023, 08 Apr (Shift 2)]

Question

YESPYQ · Accepted Answer

Options are free to see. Unlock the correct answer and full explanation with PYQ Pass.

If \(A=\left[\begin{array}{cc}1 & 5 \\ \lambda & 10\end{array}\right], A^{-1}=\alpha A+\beta I\) and \(\alpha+\b…

Practice more JEE Maths PYQs

If \(A=\left[\begin{array}{cc}1 &amp; 5 \\ \lambda &amp; 10\end{array}\right], A^{-1}=\alpha A+\beta I\) and \(\alpha+\b…

Practice more JEE Maths PYQs

If \(A=\left[\begin{array}{cc}1 & 5 \\ \lambda & 10\end{array}\right], A^{-1}=\alpha A+\beta I\) and \(\alpha+\b…