If \(\sum _{r=1}^{50}{\tan }^{-1}\frac{1}{2{r}^{2}}=p\), then the value of \(\tan p\) is: [JEE Main 2021, 26 Aug (Shift …
Q1
If \(\sum _{r=1}^{50}{\tan }^{-1}\frac{1}{2{r}^{2}}=p\), then the value of \(\tan p\) is:
[JEE Main 2021, 26 Aug (Shift 2)]
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