If $ A=\left(\begin{array}{cc}0 & \sin \alpha \ \sin \alpha & 0\end{array}\right) $ and $ \operatorname{det}\left(A^{2}-\frac{1}{2} I\right)=0 $, then a possible value of $ \alpha $ is: [JEE Main 2021, 17 Mar (Shift 1)]

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If \( A=\left(\begin{array}{cc}0 & \sin \alpha \\ \sin \alpha & 0\end{array}\right) \) and \( \operatorname{det}…

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If \( A=\left(\begin{array}{cc}0 & \sin \alpha \\ \sin \alpha & 0\end{array}\right) \) and \( \operatorname{det}…