🛠️ JEE➗ Maths

Let in a Binomial distribution, consisting of 5 independent trials, probabilities of exactly 1 and 2 successes be 0.4096…

Q1

Let in a Binomial distribution, consisting of 5 independent trials, probabilities of exactly 1 and 2 successes be 0.4096 and 0.2048 respectively. Then the probability of getting exactly 3 successes is equal to:

[JEE Main 2021, 18 Mar (Shift 2)]

a

\(\frac{40}{243}\)

b

\(\frac{128}{625}\)

c

\(\frac{80}{243}\)

d

\(\frac{32}{625}\)

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