If the function \(f(x)= \begin{cases}(1+|\cos x|) \frac{\lambda}{|\cos x|}, & 0<x<\frac{\pi}{2} \\ \mu, & …

If the function
\(f(x)= \begin{cases}(1+|\cos x|) \frac{\lambda}{|\cos x|}, & 0<x<\frac{\pi}{2} \\ \mu, & x=\frac{\pi}{2} \quad \text { is continuous at } \\ e^{\frac{\cot 6 x}{\cot 4 x}}, & \frac{\pi}{2}<x<\pi\end{cases}\) \(x=\frac{\pi}{2}\), then \(9 \lambda+6 \log _e \mu+\mu^6-e^{6 \lambda}\)

is equal to