Let a function \( \mathrm{f}:[0,5] \rightarrow \mathrm{R} \) be continuous, \( \mathrm{f}(1)=3 \) and \(F\) be defined a…

Let a function \( \mathrm{f}:[0,5] \rightarrow \mathrm{R} \) be continuous, \( \mathrm{f}(1)=3 \) and \(F\) be defined as: \( F(x)=\int_{1}^{x} t^{2} g(t) d t \), where \( g(t)=\int_{1}^{t} f(u) d u \). Then for the function \( F \), the point \( x=1 \) is :

[JEE Main 2020, 9 Jan (Shift 2)]