🛠️ JEE➗ Maths

Let \(f:R-\left{\frac{\alpha }{6}\right}\to R\) be defined by \(f(x)=\frac{5x+3}{6x-\alpha }\). Then the value of \(\alp…

Q1

Let \(f:R-\left{\frac{\alpha }{6}\right}\to R\) be defined by \(f(x)=\frac{5x+3}{6x-\alpha }\). Then the value of \(\alpha\) for which \((f∘f)(x)=x\), for all \(x\in R-\left{\frac{\alpha }{6}\right}\), is :

[JEE Main 2021, 20 Jul (Shift 2)]

a

6

b

8

c

No such \(\alpha\) exists

d

5

🔒
Answer & explanation — PYQ Pass

Options are free to see. Unlock the correct answer and full explanation with Pass.

Unlock · ₹149

Practice more JEE Maths PYQs

See every question on Relations and Functions, or browse the full JEE question bank.

See all questions on Relations and Functions →