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The time period of a simple pendulum is given by \( T=2 \pi \sqrt{\frac{l}{g}} \). The measured value of the length of p…

Q1

The time period of a simple pendulum is given by \( T=2 \pi \sqrt{\frac{l}{g}} \). The measured value of the length of pendulum is \( 10 \mathrm{~cm} \) known to a \( 1 \mathrm{~mm} \) accuracy. The time for 200 oscillations of the pendulum is found to be 100 second using a clock of 1 s resolution. The percentage accuracy in the determination of \( g \) using this pendulum is \( x \) . The value of \( x \) to be nearest integer is:-

a

\( 2 \% \)

b

\( 3 \% \)

c

\( 5 \% \)

d

\( 4 \% \)

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