🛠️ JEE➗ Maths

If a function \(f(x)\) defined by \( f(x)= \begin{cases}\mathrm{ae}^x+\mathrm{be}^{-x}, & -1 \leq x<1 \\ \mathrm{…

Q1

If a function \(f(x)\) defined by
\(
f(x)= \begin{cases}\mathrm{ae}^x+\mathrm{be}^{-x}, & -1 \leq x<1 \\ \mathrm{cx}^2 & , 1 \leq x \leq 3 \\ \mathrm{a} x^2+2 \mathrm{cx}, & 3<x \leq 4\end{cases}
\)
be continuous for some \(a, b, c \in \mathbf{R}\) and \(f^{\prime}(0)+f^{\prime}(2)=\mathrm{e}\), then the value of \(\mathrm{a}\) is :

[JEE Main 2020, 2 Sep (Shift 1)]

a

\(\frac{e}{{e}^{2}-3e+13}\)

b

\(\frac{e}{{e}^{2}+3e+13}\)

c

\(\frac{e}{{e}^{2}-3e-13}\)

d

\(\frac{1}{{e}^{2}-3e+13}\)

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