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🛠️ JEE🧪 Chemistry

The solubility product of \(\mathrm{Cr}(\mathrm{OH})_3\) at \(298 \mathrm{~K}\) is \(6.0 \times 10^{-31}\). The concentr…

Q1

The solubility product of \(\mathrm{Cr}(\mathrm{OH})_3\) at \(298 \mathrm{~K}\) is \(6.0 \times 10^{-31}\). The concentration of hydroxide ions in a saturated solution of \(\mathrm{Cr}(\mathrm{OH})_3\) will be:

a

\({\left(2.22\times {10}^{-31}\right)}^{1/4}\)

b

\({\left(18\times {10}^{-31}\right)}^{1/2}\)

c

\({\left(4.86\times {10}^{-29}\right)}^{1/4}\)

d

\({\left(18\times {10}^{-31}\right)}^{1/4}\)

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