If $A=\frac{1}{5 ! 6 ! 7 !}\left[\begin{array}{lll}5 ! & 6 ! & 7 ! \ 6 ! & 7 ! & 8 ! \ 7 ! & 8 ! & 9 !\end{array}\right]$ then $|adj(\operatorname{adj}(2 A))|$ is equal to : [JEE Main 2023, 10 Apr (Shift 2)]

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If \(A=\frac{1}{5 ! 6 ! 7 !}\left[\begin{array}{lll}5 ! & 6 ! & 7 ! \\ 6 ! & 7 ! & 8 ! \\ 7 ! & 8 ! …

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If \(A=\frac{1}{5 ! 6 ! 7 !}\left[\begin{array}{lll}5 ! &amp; 6 ! &amp; 7 ! \\ 6 ! &amp; 7 ! &amp; 8 ! \\ 7 ! &amp; 8 ! …

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If \(A=\frac{1}{5 ! 6 ! 7 !}\left[\begin{array}{lll}5 ! & 6 ! & 7 ! \\ 6 ! & 7 ! & 8 ! \\ 7 ! & 8 ! …