If \(a_n=\frac{-2}{4 n^2-16 n+15}\), then \(a_1+a_2+\ldots+a_{25}\) is equal to: [JEE Main 2023, 30 Jan (Shift 1)]
Q1
If \(a_n=\frac{-2}{4 n^2-16 n+15}\), then \(a_1+a_2+\ldots+a_{25}\) is equal to:
[JEE Main 2023, 30 Jan (Shift 1)]
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