For $x0$ ,If $ f(x)=\int_{1}^{x} \frac{\log _{e} t}{1+t} d t $ .Then $f(e)+f\left(\frac{1}{e}\right)$ is equal to [JEE Main 2021, 26 Feb (Shift 2)]

Question

For $x>0$ ,If $ f(x)=\int_{1}^{x} \frac{\log _{e} t}{1+t} d t $ .Then $f(e)+f\left(\frac{1}{e}\right)$ is equal to [JEE Main 2021, 26 Feb (Shift 2)]

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For \(x>0\) ,If \( f(x)=\int_{1}^{x} \frac{\log _{e} t}{1+t} d t \) .Then \(f(e)+f\left(\frac{1}{e}\right)\) is equal…