The electric field of a plane electromagnetic wave is given by \( \overrightarrow{\mathrm{E}}=\mathrm{E}_{0} \frac{\hat{…

The electric field of a plane electromagnetic wave is given by \( \overrightarrow{\mathrm{E}}=\mathrm{E}_{0} \frac{\hat{\mathrm{i}}+\hat{\mathrm{j}}}{\sqrt{2}} \cos (k z+\omega \mathrm{t}) \). At \( \mathrm{t}=0 \), a positively charged particle is at the point \( (x, y, z)=\left(0,0, \frac{\pi}{k}\right) \). If its instantaneous velocity at \( (t=0) \) is \( v_{0} \hat{k} \), the force acting on it due to the wave is: