🛠️ JEE➗ Maths

The \(\operatorname{sum} \sum_{n=1}^{\infty} \frac{2 n^2+3 n+4}{(2 n) !}\) is equal to:

Q1

The \(\operatorname{sum} \sum_{n=1}^{\infty} \frac{2 n^2+3 n+4}{(2 n) !}\) is equal to:

a

\(\frac{11 e}{2}+\frac{7}{2 e}\)

b

\(\frac{13 e}{4}+\frac{5}{4 e}-4\)

c

\(\frac{11 e}{2}+\frac{7}{2 e}-4\)

d

\(\frac{13 e}{4}+\frac{5}{4 e}\)

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