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\(\lim _{n \rightarrow \infty}\left(\frac{1}{1+n}+\frac{1}{2+n}+\frac{1}{3+n}+\ldots+\frac{1}{2 n}\right)\) is equal to …

Q1

\(\lim _{n \rightarrow \infty}\left(\frac{1}{1+n}+\frac{1}{2+n}+\frac{1}{3+n}+\ldots+\frac{1}{2 n}\right)\) is equal to

[JEE Main 2023, 1 Feb (Shift 1)]

a

\(0\)

b

\({\log }_{e}2\)

c

\(\log _{ e }\left(\frac{3}{2}\right)\)

d

\(\log _{ e }\left(\frac{2}{3}\right)\)

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