The pitch of the screw gauge is \(1\mathrm{mm}\) and there are 100 divisions on the circular scale. When nothing is put …

The pitch of the screw gauge is \(1\mathrm{mm}\) and there are 100 divisions on the circular scale. When nothing is put in between the jaws, the zero of the circular scale lies 8 divisions below the reference line. When a wire is placed between the jaws, the first linear scale division is clearly visible while \({72}^{\text{nd }}\)division on circular scale coincides with the reference line. The radius of the wire is:

[JEE Main 2021, 25 Feb (Shift 1)]