Let $A=\left(\begin{array}{lll}1 & 0 & 0 \ 0 & 1 & 1 \ 1 & 0 & 0\end{array}\right)$. Then $A^{2025}-A^{2020}$ is equal to: [JEE Main 2021, 26 Aug (Shift 2)]

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Let \(A=\left(\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 0\end{array}\right)\). Then \(…

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Let \(A=\left(\begin{array}{lll}1 &amp; 0 &amp; 0 \\ 0 &amp; 1 &amp; 1 \\ 1 &amp; 0 &amp; 0\end{array}\right)\). Then \(…

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Let \(A=\left(\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 1 \\ 1 & 0 & 0\end{array}\right)\). Then \(…