Let 9 distinct balls be distributed among 4 boxes, \(B_1, B_2\), \(B_3\) and \(B_4\). If the probability that \(B_3\) contains exactly 3 balls is \(k\left(\frac{3}{4}\right)^9\) then \(k\) lies in the set:

[JEE Main 2021, 25 Jul (Shift 1)]

Question

Let 9 distinct balls be distributed among 4 boxes, \(B_1, B_2\), \(B_3\) and \(B_4\). If the probability that \(B_3\) contains exactly 3 balls is \(k\left(\frac{3}{4}\right)^9\) then \(k\) lies in the set:

[JEE Main 2021, 25 Jul (Shift 1)]

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Let 9 distinct balls be distributed among 4 boxes, \(B_1, B_2\), \(B_3\) and \(B_4\). If the probability that \(B_3\) co…

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