Let the mean and variance of 8 numbers $-10,-7,-1,x,y,9,2,16$ be $\frac{7}{2}$ and $\frac{293}{4}$, respectively. Then the mean of 4 numbers $x,y,x+y+1,|x-y|$ is:

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Let the mean and variance of 8 numbers \(-10,-7,-1,x,y,9,2,16\) be \(\frac{7}{2}\) and \(\frac{293}{4}\), respectively. …

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