🛠️ JEE🧪 Chemistry

The molecular formula of second homologue in the homologous series of mono carboxylic acids is ..............

\(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}_{2}\)

\(\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}_{2}\)

\(\mathrm{C}_{2} \mathrm{H}_{2} \mathrm{O}_{2}\)

\(\mathrm{CH}_{2} \mathrm{O}\)

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