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From a lot containing \(10\) defective and \(90\) non- defective bulbs, \(8\) bulbs are selected one by one with replace…

Q1

From a lot containing \(10\) defective and \(90\) non- defective bulbs, \(8\) bulbs are selected one by one with replacement. Then the probability of getting at least \(7\) defective bulbs is

[JEE Main 2026, 24 Jan (Shift 1)]

a

\(\frac{67}{{10}^{8}}\)

b

\(\frac{81}{{10}^{8}}\)

c

\(\frac{7}{{10}^{7}}\)

d

\(\frac{73}{{10}^{8}}\)

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