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The integral \({\int }_{0}^{\pi }\frac{8xdx}{4{\cos }^{2}x+{\sin }^{2}x}\) is equal to [JEE Main 2025, 3 Apr (Shift 2)]

Q1

The integral \({\int }_{0}^{\pi }\frac{8xdx}{4{\cos }^{2}x+{\sin }^{2}x}\) is equal to

[JEE Main 2025, 3 Apr (Shift 2)]

a

\(2{\pi }^{2}\)

b

\(4{\pi }^{2}\)

c

\({\pi }^{2}\)

d

\(\frac{3{\pi }^{2}}{2}\)

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