Consider two sets $A$and $B$, each containing three numbers in A.P. Let the sum and the product of the elements of $A$ be $36$and $p$ respectively and the sum and the product of the elements of $B$be $36$ and $q$respectively. Let $d$ and $D$be the common differences of AP's in $A$ and $B$respectively such that $\mathrm{D}=\mathrm{d}+3,\mathrm{d}0$. If $\frac{\mathrm{p}+\mathrm{q}}{\mathrm{p}-\mathrm{q}}=\frac{19}{5}$, then $\mathrm{p}-\mathrm{q}$ is equal to [JEE Main 2025, 4 Apr (Shift 1)]

Question

Consider two sets $A$and $B$, each containing three numbers in A.P. Let the sum and the product of the elements of $A$ be $36$and $p$ respectively and the sum and the product of the elements of $B$be $36$ and $q$respectively. Let $d$ and $D$be the common differences of AP's in $A$ and $B$respectively such that $\mathrm{D}=\mathrm{d}+3,\mathrm{d}>0$. If $\frac{\mathrm{p}+\mathrm{q}}{\mathrm{p}-\mathrm{q}}=\frac{19}{5}$, then $\mathrm{p}-\mathrm{q}$ is equal to [JEE Main 2025, 4 Apr (Shift 1)]

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Consider two sets \(A\)and \(B\), each containing three numbers in A.P. Let the sum and the product of the elements of \…

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