The angle between vector \(\vec{Q}\) and the resultant of \((2\vec{Q}+2\vec{P})\) and \((2\vec{Q}-2\vec{P})\) is

\(0^\circ\)

\({\tan }^{-1}\frac{P}{Q}\)

\({\tan }^{-1}\left(\frac{2\vec{Q}-2\vec{P}}{2\vec{Q}+2\vec{P}}\right)\)

\({\tan }^{-1}(2Q/P)\)