🛠️ JEE🧪 Chemistry

Combustion of 1 mole of benzene is expressed at \({C}_{6}{H}_{6}(l)+\frac{15}{2}{O}_{2}(g)\to 6C{O}_{2}(g)+3{H}_{2}O(l)\…

Q1

Combustion of 1 mole of benzene is expressed at
\({C}_{6}{H}_{6}(l)+\frac{15}{2}{O}_{2}(g)\to 6C{O}_{2}(g)+3{H}_{2}O(l)\text{. }\)

The standard enthalpy of combustion of 2 mol of benzene is \({{}^{'}x}^{'}kJ\).
\(x=\)__________

Given :
1. Standard Enthalpy of formation of 1 mol of \({C}_{6}{H}_{6}(l)\) , for the reaction \(6\mathrm{C}\)(graphite) \(+3{H}_{2}(g)\to {C}_{6}{H}_{6}(l)\) is 48.5 kJ/mol
2. Standard Enthalpy of formation of 1 mol of \(C{O}_{2}(g)\), for the reaction \(\mathrm{C}\)(graphite)\(+{O}_{2}(g)\to C{O}_{2}(g)\) is -393.5 kJ/mol
3. Standard and Enthalpy of formation of 1 mol of \({H}_{2}O(l)\) , for the reaction \({H}_{2}(g)+\frac{1}{2}{O}_{2}(g)\to {H}_{2}O(l)\) -286 kJ/mol

[JEE Main 2024, 5 Apr (Shift 2)]

a

3268

b

6535

c

2535

d

6438

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