If $7=5+\frac{1}{7}(5+\alpha)+\frac{1}{7^2}(5+2 \alpha)+\ldots \infty$ terms, then $\alpha$ is equal to (24 Jan, Shift II, Memory Based)

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If \(7=5+\frac{1}{7}(5+\alpha)+\frac{1}{7^2}(5+2 \alpha)+\ldots \infty\) terms, then \(\alpha\) is equal to (24 Jan, Shi…