If the mean deviation about the median of the numbers $k, 2 k, 3 k, \ldots, 1000 k$ is $500$, then $k^2$ is equal to:

[JEE Main 2026, 22 Jan (Shift 2)]

Question

If the mean deviation about the median of the numbers $k, 2 k, 3 k, \ldots, 1000 k$ is $500$, then $k^2$ is equal to: [JEE Main 2026, 22 Jan (Shift 2)]

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If the mean deviation about the median of the numbers \(k, 2 k, 3 k, \ldots, 1000 k\) is \(500\), then \(k^2\) is equal …

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