$ \begin{aligned} & A=\{1,2,3, \ldots, 10\}, \ & B=\left\{\frac{m}{n}, nm, m, n \in A, \operatorname{gcd}(m \cdot n)=1\right\} \end{aligned} $ Then no. of elements in $\mathrm{B}=$ ?

Question

$ \begin{aligned} & A=\{1,2,3, \ldots, 10\}, \ & B=\left\{\frac{m}{n}, n>m, m, n \in A, \operatorname{gcd}(m \cdot n)=1\right\} \end{aligned} $ Then no. of elements in $\mathrm{B}=$ ?

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\( \begin{aligned} & A=\{1,2,3, \ldots, 10\}, \\ & B=\left\{\frac{m}{n}, n>m, m, n \in A, \operatorname{gcd}(…

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\( \begin{aligned} &amp; A=\{1,2,3, \ldots, 10\}, \\ &amp; B=\left\{\frac{m}{n}, n&gt;m, m, n \in A, \operatorname{gcd}(…

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\( \begin{aligned} & A=\{1,2,3, \ldots, 10\}, \\ & B=\left\{\frac{m}{n}, n>m, m, n \in A, \operatorname{gcd}(…