Let $\sum _{k=1}^{n}{a}_{k}=\alpha {n}^{2}+\beta n$. If ${a}_{10}=59$ and ${a}_{6}=7{a}_{1}$, then $\alpha+\beta$ is equal to [JEE Main 2026, 23 Jan (Shift 2)]

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Let \(\sum _{k=1}^{n}{a}_{k}=\alpha {n}^{2}+\beta n\). If \({a}_{10}=59\) and \({a}_{6}=7{a}_{1}\), then \(\alpha+\beta\…

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