If \(\frac{1}{{1}^{4}}+\frac{1}{{2}^{4}}+\frac{1}{{3}^{4}}+\ldots ..\infty =\frac{{\pi }^{4}}{90}\), \(\frac{1}{{1}^{4}}…

If \(\frac{1}{{1}^{4}}+\frac{1}{{2}^{4}}+\frac{1}{{3}^{4}}+\ldots ..\infty =\frac{{\pi }^{4}}{90}\), \(\frac{1}{{1}^{4}}+\frac{1}{{3}^{4}}+\frac{1}{{5}^{4}}+\ldots ..\infty =\alpha ,\) \(\frac{1}{{2}^{4}}+\frac{1}{{4}^{4}}+\frac{1}{{6}^{4}}+\ldots ..\infty =\beta ,\) then \(\frac{\alpha }{\beta }\) is equal to

[JEE Main 2025, 8 Apr (Shift 1)]