YESPYQ Start Practice
🛠️ JEE➗ Maths

The integral \({\int }_{0}^{\pi }\frac{(\mathrm{x}+3)\mathrm{sinx}}{1+3{\cos }^{2}\mathrm{x}}\mathrm{dx}\) is equal to :…

Q1

The integral \({\int }_{0}^{\pi }\frac{(\mathrm{x}+3)\mathrm{sinx}}{1+3{\cos }^{2}\mathrm{x}}\mathrm{dx}\) is equal to :

[JEE Main 2025, 7 Apr (Shift 1)]

a

\(\frac{\pi }{\sqrt{3}}(\pi +1)\)

b

\(\frac{\pi }{\sqrt{3}}(\pi +2)\)

c

\(\frac{\pi }{3\sqrt{3}}(\pi +6)\)

d

\(\frac{\pi }{2\sqrt{3}}(\pi +4)\)

🔒
Answer & explanation — PYQ Pass

Options are free to see. Unlock the correct answer and full explanation with Pass.

Unlock · ₹149
← Previous questionNext question →

Practice more JEE Maths PYQs

See every question on Definite Integration, or browse the full JEE question bank.

See all questions on Definite Integration →