🛠️ JEE➗ Maths

The function \(f(x)=\frac{x}{x^2-6 x-16}, x \in R -\{-2,8\}\) [JEE Main 2024, 29 Jan (Shift 2)]

The function \(f(x)=\frac{x}{x^2-6 x-16}, x \in R -\{-2,8\}\)

[JEE Main 2024, 29 Jan (Shift 2)]

decreases in \((-\infty,-2)\) and increases in \((8, \infty)\)

decreases in \((-\infty,-2) \cup(-2,8) \cup(8, \infty)\)

increases in \((-\infty,-2) \cup(-2,8) \cup(8, \infty)\)

decreases in \((-2,8)\) and increases in \((-\infty,-2) \cup(8, \infty)\)

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