🛠️ JEE➗ Maths

The sum of the series \(\frac{1}{1-3 \cdot 1^2+1^4}+\frac{2}{1-3 \cdot 2^2+2^4}+\frac{3}{1-3 \cdot 3^2+3^4}+\ldots\) up …

Q1

The sum of the series \(\frac{1}{1-3 \cdot 1^2+1^4}+\frac{2}{1-3 \cdot 2^2+2^4}+\frac{3}{1-3 \cdot 3^2+3^4}+\ldots\) up to \(10\) terms is

[JEE Main 2024, 31 Jan (Shift 1)]

a

\(-\frac{55}{109}\)

b

\(\frac{55}{109}\)

c

\(\frac{45}{109}\)

d

\(-\frac{45}{109}\)

🔒
Answer & explanation — PYQ Pass

Options are free to see. Unlock the correct answer and full explanation with Pass.

Unlock · ₹149

Practice more JEE Maths PYQs

See every question on Sequence and Series, or browse the full JEE question bank.

See all questions on Sequence and Series →