\(1+3+{5}^{2}+7+{9}^{2}+\ldots\) up to \(40\) terms is equal to [JEE Main 2025, 4 Apr (Shift 1)]
Q1
\(1+3+{5}^{2}+7+{9}^{2}+\ldots\) up to \(40\) terms is equal to
[JEE Main 2025, 4 Apr (Shift 1)]
🔒
Answer & explanation — PYQ Pass
Unlock · ₹149
Options are free to see. Unlock the correct answer and full explanation with Pass.
Practice more JEE Maths PYQs
See every question on Sequence and Series, or browse the full JEE question bank.
See all questions on Sequence and Series →