🛠️ JEE➗ Maths

\(\sum _{n=1}^{10}\left(\frac{528}{n(n+1)(n+2)}\right)\) is equal to: [JEE Main 2026, 5 Apr (Shift 1)]

Q1

\(\sum _{n=1}^{10}\left(\frac{528}{n(n+1)(n+2)}\right)\) is equal to:


[JEE Main 2026, 5 Apr (Shift 1)]

a

\(65\)

b

\(130\)

c

\(220\)

d

\(440\)

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