For a distribution of 10 observations, \(\sum_{i=1}^{10} x_i=55\) and \(\sum_{i=1}^{10} x_i^2=328\) If the observations …
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For a distribution of 10 observations, \(\sum_{i=1}^{10} x_i=55\) and \(\sum_{i=1}^{10} x_i^2=328\) If the observations 4 and 5 are replaced by 6 and 8 respectively, then the new variance is
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