A proton is moving with a uniform velocity of \(2\times 1{0}^{8}\text{ }\text{m/s}\) in uniform magnetic and electric fi…
Q1
A proton is moving with a uniform velocity of \(2\times 1{0}^{8}\text{ }\text{m/s}\) in uniform magnetic and electric fields, which are perpendicular to each other. If the electric field is switched off, the proton moves in a circular path of radius \(1.6\times 1{0}^{−5}\text{ }\text{m}\). The magnetic field (\(B\)) is:
(Shift II Memory Based)
🔒
Answer & explanation — PYQ Pass
Unlock · ₹149
Options are free to see. Unlock the correct answer and full explanation with Pass.
Practice more JEE Physics PYQs
See every question on Moving Charges and Magnetism, or browse the full JEE question bank.
See all questions on Moving Charges and Magnetism →