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A proton is moving with a uniform velocity of \(2\times 1{0}^{8}\text{ }\text{m/s}\) in uniform magnetic and electric fi…

Q1

A proton is moving with a uniform velocity of \(2\times 1{0}^{8}\text{ }\text{m/s}\) in uniform magnetic and electric fields, which are perpendicular to each other. If the electric field is switched off, the proton moves in a circular path of radius \(1.6\times 1{0}^{−5}\text{ }\text{m}\). The magnetic field (\(B\)) is:

(Shift II Memory Based)

a

\(5\times 1{0}^{−5}\text{ }\text{T}\)

b

\(1.3\times 1{0}^{5}\text{ }\text{T}\)

c

\(2.5\times 1{0}^{4}\text{ }\text{T}\)

d

\(2.5\times 1{0}^{2}\text{ }\text{T}\)

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