If $f: \mathbb{R} \rightarrow \mathbb{R}, g: \mathbb{R} \rightarrow \mathbb{R}$ are defined by $f(x)=5 x-3, g(x)=x^2+3$, then $g \circ f^{-1}(3)$ is equal to

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YESPYQ · Accepted Answer

Correct answer: b) $\frac{111}{25}$. $f(x)=5x-3\ {\mathrm{f}}^{-1}(\mathrm{x})=\frac{\mathrm{x}+3}{5}\ \text{Now},\ g(x)={x}^{2}+3\ {gof}^{-1}(3)=g\left({f}^{-1}(3)\right)\ =g\left(\frac{6}{5}\right)=\frac{111}{25}$

If \(f: \mathbb{R} \rightarrow \mathbb{R}, g: \mathbb{R} \rightarrow \mathbb{R}\) are defined by \(f(x)=5 x-3, g(x)=x^2+…

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