A $3$ m long wire of radius $3$ mm shows an extension of $0.1$ mm when loaded vertically by a mass of $50$ kg in an experiment to determine Young's modulus. The value of Young's modulus of the wire as per this experiment is $\mathrm{P}\times {10}^{11}{\mathrm{Nm}}^{-2}$, where the value of P is: ( Take $\mathrm{g}=3\pi \mathrm{m}/{\mathrm{s}}^{2}$) [JEE Main 2025, 8 Apr (Shift 1)]

Question

YESPYQ · Accepted Answer

Correct answer: a) $5$. $\begin{matrix}Y=\frac{F\times L}{A\times \Delta l} \ F=50\times 3\pi \ A=\pi \times {\left({3\times 10}^{-3}\right)}^{2} \ =5\times {10}^{11} \ P=5\end{matrix}$

A \(3\) m long wire of radius \(3\) mm shows an extension of \(0.1\) mm when loaded vertically by a mass of \(50\) kg in…

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