The temperature of a body in air falls from \(40^\circ C\) to \(24^\circ C\) in 4 minutes. The temperature of the air is…

From Newton's law of cooling

\(\frac{{T}_{2}-{T}_{1}}{t}=K\left[\frac{{T}_{2}+{T}_{1}}{2}-{T}_{s}\right]\\ {T}_{1}=24^\circ C;{T}_{2}=40^\circ C,t=4,{T}_{s}=16^\circ C\\ \frac{40-24}{4}=K[32-16]\\ K=\frac{1}{4}\)

Let T be final temp.

\(\frac{24-T}{4}=K\left[\frac{T+24}{2}-16\right]\)

From equation (i) &(ii)

\(T=\frac{56}{3}{}^{o}C\)