If 50 Vernier divisions are equal to 49 main scale divisions of a travelling microscope and one smallest reading of main scale is 0.5 mm, the Vernier constant of travelling microscope is:

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Correct answer: d) 0.01 mm. \begin{aligned} & \text { (d) } 50 \mathrm{~V}+\mathrm{S}=49 \mathrm{~S}+\mathrm{S} \ & \mathrm{~S}=50(\mathrm{~S}-\mathrm{V}) \ & 0.5=50(\mathrm{~S}-\mathrm{V}) \end{aligned} The Vernier constant of travelling microscope is $S-V=\frac{0.5}{50}=\frac{1}{100}=0.01mm$

If 50 Vernier divisions are equal to 49 main scale divisions of a travelling microscope and one smallest reading of main…

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