If 50 Vernier divisions are equal to 49 main scale divisions of a travelling microscope and one smallest reading of main…

$$\begin{aligned}& \text { (d) } 50 \mathrm{~V}+\mathrm{S}=49 \mathrm{~S}+\mathrm{S} \\& \mathrm{~S}=50(\mathrm{~S}-\mathrm{V}) \\& 0.5=50(\mathrm{~S}-\mathrm{V})\end{aligned}$$
The Vernier constant of travelling microscope is \(S-V=\frac{0.5}{50}=\frac{1}{100}=0.01mm\)