In a process, the pressure of a gas is directly proportional to its temperature. Choose the correct options: A: The proc…
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In a process, the pressure of a gas is directly proportional to its temperature. Choose the correct options:
A: The process is isochoric.
B: Work done in the process is zero.
C: Internal energy increases with an increase in temperature.
(Shift I - Memory Based)
✓ Correct answer: c)
A,B, and C are correct.
ExplanationSolution:
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Condition:
- If pressure \(P\propto T\), this implies: \(P=kT\ \text{(where }k\text{ is constant)}\mathrm{.}\)
- This relationship is only valid if the volume \(V\) is constant, as per the ideal gas law:
- \(PV=nRT\ \text{ }⟹\text{ }\ P\propto T\ \text{(if }V\text{ is constant)}\mathrm{.}\).
- Thus, the process is isochoric (the statement \(A\) is correct).
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Work Done:
- In an isochoric process, the volume remains constant (\(\Delta V=0\)), so the work done: \(W=P\Delta V=0.\) Hence, \(B\) is also correct.
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Internal Energy:
- The internal energy \(U\) of an ideal gas depends on temperature: \(\Delta U=n{C}_{v}\Delta T\mathrm{.}\). Since temperature increases, internal energy also increases. Thus, \(C\) is correct.
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Conclusion:
- All statements \(A\), \(B\), and \(C\) are correct.
Answer: (3) \(A,B,\) and \(C\) are correct.
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