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In a process, the pressure of a gas is directly proportional to its temperature. Choose the correct options: A: The proc…

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In a process, the pressure of a gas is directly proportional to its temperature. Choose the correct options:

A: The process is isochoric.
B: Work done in the process is zero.
C: Internal energy increases with an increase in temperature.

(Shift I - Memory Based)

a

A and B are correct.

b

A and C are correct.

c

A,B, and C are correct.

d

B and C are correct.

✓ Correct answer: c)

A,B, and C are correct.

ExplanationSolution:
  1. Condition:

    • If pressure \(P\propto T\), this implies: \(P=kT\ \text{(where }k\text{ is constant)}\mathrm{.}\)
    • This relationship is only valid if the volume \(V\) is constant, as per the ideal gas law:
    • \(PV=nRT\ \text{  }⟹\text{  }\ P\propto T\ \text{(if }V\text{ is constant)}\mathrm{.}\).
    • Thus, the process is isochoric (the statement \(A\) is correct).
  2. Work Done:

    • In an isochoric process, the volume remains constant (\(\Delta V=0\)), so the work done: \(W=P\Delta V=0.\) Hence, \(B\) is also correct.
  3. Internal Energy:

    • The internal energy \(U\) of an ideal gas depends on temperature: \(\Delta U=n{C}_{v}\Delta T\mathrm{.}\). Since temperature increases, internal energy also increases. Thus, \(C\) is correct.
  4. Conclusion:

    • All statements \(A\), \(B\), and \(C\) are correct.

Answer: (3) \(A,B,\) and \(C\) are correct.

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